Full teaching narration is free with Private Starter.Create free account
Back to curriculum
MathematicsGrade 6· Indiana Academic Standards (IDOE)
Aligned to:Indiana Academic Standards / Common Core (Math)

Area of Triangles and Composite Figures

Students derive and apply area formulas for triangles, quadrilaterals, and composite figures in real-world settings.

Area of Triangles and Composite Figures

Illustrations are auto-generated and may be placeholders. They can be refreshed to match the narration.

Full teaching narration is included free with a Private Starter account.Create free account

Review Rectangle Area

Area measures the number of square units needed to cover a flat region without gaps or overlaps. For a rectangle, multiply its length by its width: A = l × w. This works because the rectangle can be arranged in equal rows and columns of unit squares. For example, a rectangle that is 8 centimeters long and 5 centimeters wide contains 5 rows of 8 square centimeters. Its area is 8 × 5 = 40 square centimeters. Always write area with square units, such as cm², m², or ft². Do not confuse area with perimeter. Perimeter measures the distance around a figure, while area measures the surface inside it.

A gridded rectangle shows a length of 8 centimeters, a width of 5 centimeters, an inside area of 40 square centimeters, and perimeter around the edge.
A gridded rectangle shows a length of 8 centimeters, a width of 5 centimeters, an inside area of 40 square centimeters, and perimeter around the edge.Source: Illustrated for this lesson

Derive the Triangle Formula

A triangle’s area can be derived by using a shape whose area is already known. Make a copy of a triangle and rotate the copy so the two triangles form a parallelogram. The parallelogram has the same base b and perpendicular height h as the original triangle. Its area is b × h. Because the two matching triangles divide the parallelogram into equal halves, one triangle has area A = ½bh. The height must meet the base at a right angle; a slanted side is not always the height. For example, a triangle with a base of 10 meters and a perpendicular height of 6 meters has area ½ × 10 × 6 = 30 square meters.

Two matching triangles combine to form a parallelogram with its base and perpendicular height marked.
Two matching triangles combine to form a parallelogram with its base and perpendicular height marked.Source: Illustrated for this lesson

Find Quadrilateral Areas

A quadrilateral is a polygon with four sides. Rectangles and squares use length times width, while a parallelogram uses A = bh, where h is the perpendicular height. A trapezoid has exactly one pair of parallel sides called bases. Its area is A = ½(b₁ + b₂)h because two matching trapezoids can form a parallelogram whose base is b₁ + b₂. Suppose a trapezoid has bases of 12 centimeters and 8 centimeters and a height of 5 centimeters. Its area is ½(12 + 8) × 5 = ½ × 20 × 5 = 50 square centimeters. For any quadrilateral, you may also draw a diagonal or divide the figure into rectangles and triangles, then add their areas.

A labeled trapezoid shows two parallel bases, a perpendicular height, and an area calculation.
A labeled trapezoid shows two parallel bases, a perpendicular height, and an area calculation.Source: Illustrated for this lesson

Decompose Composite Figures

A composite figure is made from two or more simpler shapes. To find its area, decompose it into rectangles, triangles, or other familiar polygons. Add the areas of pieces that make the figure, or subtract the area of a missing piece from a larger shape. Consider an L-shaped floor that fits inside a 10-meter by 8-meter rectangle. A 4-meter by 3-meter rectangular corner is missing. The large rectangle has area 10 × 8 = 80 square meters, and the missing rectangle has area 4 × 3 = 12 square meters. Therefore, the floor’s area is 80 − 12 = 68 square meters. Check that pieces do not overlap and that every part is counted exactly once.

An L-shaped floor is shown inside a 10-meter-by-8-meter rectangle with a 4-meter-by-3-meter corner missing.
An L-shaped floor is shown inside a 10-meter-by-8-meter rectangle with a 4-meter-by-3-meter corner missing.Source: Illustrated for this lesson

Solve Measurement Problems

Area formulas help solve real-world measurement problems involving floors, walls, gardens, and signs. Begin by sketching the region, labeling measurements, and choosing how to compose or decompose it. Then calculate each area, combine the results, and use square units. Suppose a wall is an 8-meter by 3-meter rectangle topped by a triangular gable with base 8 meters and height 2 meters. The rectangle’s area is 24 square meters, and the triangle’s area is ½ × 8 × 2 = 8 square meters. A 2-meter by 1.5-meter window covers 3 square meters. The paintable area is 24 + 8 − 3 = 29 square meters. If one can covers 10 square meters, three cans are needed because two cans are not enough.